( 3 س3 - 2 ب )( 3 س3 + 2 ب ) هو ؟
حل السؤال ( 3 س3 - 2 ب )( 3 س3 + 2 ب ) هو بيت العلم، بالخطوات الصحيحة لكل الطلاب الباحثين عن الإجابة الصحيحة والمعتمدة للحصول على الدرجة الكاملة.
( 3 س3 - 2 ب )( 3 س3 + 2 ب ) هو ؟
الـجـواب :
٩س٦-٤ب٢.
( 3 س3 - 2 ب )( 3 س3 + 2 ب ) هو : شرح الإجابة
The expression (3س3 - 2ب)(3س3 + 2ب) represents the product of two binomials. To find the product, we can use the distributive property of multiplication.
First, let's expand the expression by multiplying each term in the first binomial by each term in the second binomial:
(3س3 - 2ب)(3س3 + 2ب) = 3س3 * 3س3 + 3س3 * 2ب - 2ب * 3س3 - 2ب * 2ب
Now, let's simplify each term:
3س3 * 3س3 = 9س6 (we multiply the coefficients, 3 * 3, and add the exponents, س3 * س3 = س6) 3س3 * 2ب = 6س3ب (we multiply the coefficients, 3 * 2, and keep the variables س3 and ب) -2ب * 3س3 = -6س3ب (we multiply the coefficients, -2 * 3, and keep the variables س3 and ب) -2ب * 2ب = -4ب2 (we multiply the coefficients, -2 * 2, and add the exponents, ب * ب = ب2)
Putting it all together, the product is:
9س6 + 6س3ب - 6س3ب - 4ب2
The middle terms, 6س3ب and -6س3ب, cancel each other out since they have the same magnitude but opposite signs. So, we are left with:
9س6 - 4ب2
Therefore, the expression (3س3 - 2ب)(3س3 + 2ب) simplifies to 9س6 - 4ب2.
